If , show that A2 – 5A + 7I = O. Hence find A–1.
We have A2 = A.A = .
So A2 – 5A + 7I =
Hence A2 – 5A + 7I = 0
∴ A.A – 5A = -7I
Now post multiply with A-1
So A.A.A-1-5A.A-1 = -7I.A-1
→ A.I – 5I = -7I.A-1 {since A.A-1 = I}
A – 5I = -7A-1 {since X.I = X}