If A is an invertible matrix of order 2, then det (A –1 ) is equal to

Question

Philoid · Accepted Answer

{since adj(A) is of order n and |Adj(A)| = |A|^n-1}

Alternative-

We know that AA^-1 = I

So |A||A^-1| = |I| = 1

If A is an invertible matrix of order 2, then det (A–1) is equal to