Fill in the blanks
The result tan–1 x – tan–1 is true when value of xy is _________.
The result tan–1 x – tan–1 is true when value of xy is > -1.
We have,
Principal range of tan-1a is
Let tan-1x = A and tan-1y = B … (1)
So, A,B ϵ
We know that, … (2)
From (1) and (2), we get,
Applying, tan-1 both sides, we get,
As, principal range of tan-1a is .
So, for tan-1tan(A-B) to be equal to A-B,
A-B must lie in – (3)
Now, if both A,B < 0, then A, B ϵ
∴ A ϵ and -B ϵ
So, A – B ϵ
So, from (3),
tan-1tan(A-B) = A-B
Now, if both A,B > 0, then A, B ϵ
∴ A ϵ and -B ϵ
So, A – B ϵ
So, from (3),
tan-1tan(A-B) = A-B
Now, if A > 0 and B < 0,
Then, A ϵ and B ϵ
∴ A ϵ and -B ϵ
So, A – B ϵ (0,π)
But, required condition is A – B ϵ
As, here A – B ϵ (0,π), so we must have A – B ϵ
Applying tan on both sides,
As,
So, tan A < - cot B
Again,
So,
⇒ tan A tan B < -1
As, tan B < 0
xy > -1
Now, if A < 0 and B > 0,
Then, A ϵ and B ϵ
∴ A ϵ and -B ϵ
So, A – B ϵ (-π,0)
But, required condition is A – B ϵ
As, here A – B ϵ (0,π), so we must have A – B ϵ
Applying tan on both sides,
As,
So, tan B > - cot A
Again,
So,
⇒ tan A tan B > -1
⇒xy > -1