Given find BA and use this to solve the system of equations y + 2z = 7, x – y = 3, 2x + 3y + 4z = 17.
We have,
BA = 6I …(i)
Now, given system of equations is:
y + 2z = 7,
x – y = 3,
2x + 3y + 4z = 17
So,
Applying R1→ R2, we get
Applying R2→ R3, we get
Now, …(ii)
So, BA = 6I [from eq(i)]
and
Now, putting the value of B-1, in eq. (ii), we get
⇒
∴ x = 4 , y = 2 and z = -1