Given
find BA and use this to solve the system of equations y + 2z = 7, x – y = 3, 2x + 3y + 4z = 17.
We have, 




BA = 6I …(i)
Now, given system of equations is:
y + 2z = 7,
x – y = 3,
2x + 3y + 4z = 17
So,

Applying R1→ R2, we get

Applying R2→ R3, we get

Now,
…(ii)
So, BA = 6I [from eq(i)]
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and 

Now, putting the value of B-1, in eq. (ii), we get


⇒

∴ x = 4 , y = 2 and z = -1