The area of a triangle with vertices (–3, 0), (3, 0) and (0, k) is 9 sq. units. The value of k will be


We know that, the area of a triangle with vertices (x1, y1), (x2, y2), (x3, y3) is given by


[given]



Now, expanding along second column, we get


-(k) {-3 – 3} = 18


-k (-6) = 18


6k = 18


k = 3


Hence, the correct option is (b)

26
1