If x, y, z are all different from zero and , then value of x-1 + y-1 + z-1 is


Given


Applying C1 C �1 – C3 and C2 C2 – C3,



Expanding along R1,


x [y (1 + z) + z] – 0 + 1 (yz) = 0


xy + xyz + xz + yz = 0


Dividing by xyz on both sides,




Hence, option (D) satisfies.

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