If x, y, z are all different from zero and , then value of x-1 + y-1 + z-1 is
Given
Applying C1→ C �1 – C3 and C2→ C2 – C3,
⇒
Expanding along R1,
⇒ x [y (1 + z) + z] – 0 + 1 (yz) = 0
⇒ xy + xyz + xz + yz = 0
Dividing by xyz on both sides,
Hence, option (D) satisfies.