Prove:


Given:



Using partial differentiation:





1 = Ax2 +Ax+ B+Bx+ Cx2


1 = B + (A+B)x + (A+C)x2


Equating the coefficients of x, x2 and constant value. We get:


(a) B = 1


(b) A + B = 0 A = -B A = -1


( c) A + C =0 C = -A C = 1


Put these values in equation (1)











L.H.S = R.H.S


Hence proved.


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