Find the equation of the circle which touches the both axes in first quadrant and whose radius is a.
the circle touches both the x and y axes in the first quadrant and the radius is a.
For a circle of radius a, the centre is (a,a).
The equation of a circle having centre (h,k), having radius as "r" units, is
(x – h)2 + (y – k)2 = r2
Therefore, the equation of the circle becomes (x – a)2 + (y – a)2 = a2
x2 - 2ax + a2 + y2 - 2ay + a2 - a2 = 0
x2 - 2ax + y2 - 2ay + a2 = 0
1