A chord of a circle of radius 42 cm subtends an angle of measure 60 at the centre. Find the area of the minor segment of the circle. ( = 1.73)

Question

Philoid · Accepted Answer

radius of the circle (r) = 42 cm

angle of measure (θ) = 60^o

area of the segment =

=

= 923.16 cm²

since the center angle of measure is 60^o that is a equilateral triangle.

side of the triangle (a) = 42 cm

area of the equilateral triangle =

=

= 762.93 cm²

area of minor segment (BDC) = area of segment – area of triangle

= 923.16 – 762.93

= 160.23 cm²