In the adjoining figure circles with centres X and Y touch each other at point Z. A secant passing through Z intersects the circles at points A and B respectively. Prove that, radius XA || radius YB. Fill in the blanks and complete the proof.


Construction: Draw segments XZ and ..YZ........ .


Proof: By theorem of touching circles, points X, Z, Y are ..concyclic........ .


.. YZB ........vertically opposite angles


Let ..... (I)


Now, seg XA seg XZ ........ (...radius of the same circle.......)


= .... XZA...... = a ........ (isosceles triangle theorem) (II)


similarly, seg YB .YZ......... ........ (.radius of the same circle.........)


.ZBY......... = a ........ (.isosceles triangle theorem.........) (III)


from (I), (II), (III),


XAZ = . ZBY.........


radius XA || radius YB .......... (..since alternate interior angles are equal........)



Construction: Draw segments XZ and YZ.


Proof: By theorem of touching circles, points X, Z, Y are concyclic.


XZA = YZB {vertically opposite angles}


Let XZA = BZY = a (I)


Now, seg XA segXZ (radius of the same circle)


XAZ = XZA = a (isosceles triangle theorem) (II)


Similarly, seg YB YZ (radius of the same circle)


BZY = ZBY = a (isosceles triangle theorem) (III)


from (I), (II), (III),


XAZ = ZBY


radius XA || radius YB (since alternate interior angles are equal)


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