Match the questions given under Column I with their appropriate answers given under the Column II.

Question

Philoid · Accepted Answer

(a) Given:

Here, , and

Hence, the given numbers is in G.P with common ration 1/4

∴ (a) ↔ (iii)

(b) Given: 2, 3, 5, 7

Here, a₂ – a₁ = 3 – 2 = 1

a₃ – a₂ = 5 – 3 = 2

a₄ – a₃ = 7 – 5 = 2

∴ a₂ – a₁≠ a₃ – a₂

Hence, it is not in AP

Now, we will check the ratio

,

So,

So, it is not a G.P

Hence, it is a sequence

∴ (b) ↔ (ii)

(c) 13, 8, 3, -2, -7

Here, a₂ – a₁ = 8 – 13 = -5

a₃ – a₂ = 3 – 8 = -5

a₄ – a₃ = -2 – 3 = -5

∴ a₂ – a₁= a₃ – a₂

Hence, it is an AP

∴ (c) ↔ (i)