. Let f: R → R; f(x)=
,where c is a constant. Find
(i) (cf) (x)
(ii) (c2 f) (x)
(iii) ![]()
Given:
f(x)= ![]()
(i) To find:(cf) (x)
(cf)(x) = c.f(x)
=c.![]()
= x
Therefore,
(cf)(x) = x
(ii) To find: (c2f) (x)
(c2f) (x) = c2. f(x)
= c.![]()
= cx
Therefore,
(c2f) (x) = cx
(iii) To find![]()
=
.f(x)
![]()
Therefore,
![]()