Using the principle of mathematical induction, prove each of the following for all n ϵ N:
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To Prove:
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For n = 1
LHS = ![]()
RHS = ![]()
Hence, LHS = RHS
P(n) is true for n = 1
Assume P(k) is true
……(1)
We will prove that P(k + 1) is true
RHS = ![]()
LHS =
[ Writing the Last second term ]
= ![]()
=
[ Using 1 ]
= ![]()
= ![]()
=
( Taking LCM and simplifying )
= ![]()
= RHS
Therefore,
= ![]()
LHS = RHS
Therefore, P (k + 1) is true whenever P(k) is true.
By the principle of mathematical induction, P(n) is true for
where n is a natural number
Put k = n - 1
= ![]()
Hence proved.