Evaluate:
(i) i19
(ii) i62
(ii) i373.
We all know that i = √(-1) .
and
= 1
= i (where n is any positive integer )
=![]()
= -1
So,
(i) L.H.S = ![]()
= ![]()
= ![]()
Since it is of the form ![]()
Hence the value of
.
(ii) ![]()
![]()
![]()
so its solution would be -1
(iii) ![]()
![]()
![]()
⇒i
So, it is of the form of
so the solution would be i.