If
, where c is real, prove that a2 + b2 = 1 and
.
Consider the given equation,
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Now, rationalizing
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[(a – b)(a + b) = a2 – b2]
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[i2 = -1]
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On comparing both the sides, we get
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Now, we have to prove that a2 + b2 = 1
Taking LHS,
a2 + b2
Putting the value of a and b, we get

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= 1
= RHS
Now, we have to prove ![]()
Taking LHS, ![]()
Putting the value of a and b, we get

Hence Proved