Write z = (–1 + i
) in polar form.
we have, z = (–1 + i
)
Let -1 = rcosθ and √3 = rsinθ
By squaring and adding, we get
(-1)2 + (√3)2 = (rcosθ)2 + (rsinθ)2
⇒ 1+3 = r2(cos2θ + sin2θ)
⇒4 = r2
⇒ r = 2
Since, θ lies in second quadrant, we have
Thus, the required polar form is 
1