Solve < 1, when x ϵ R.
Observe that is zero at x = 5 and not defined at x = 2
Hence plotting these two points on number line
Now for x > 5, is negative
For every root and not defined value of the sign will change
We want the negative part hence x < 2 and x > 5
x < 2 means x is from negative infinity to 2 and x > 5 means x is from 5 to infinity
Hence x ∈ (-∞, 2) U (5, ∞)
Hence solution of is x ∈ (-∞, 2) U (5, ∞)