Solve , when x ϵ R.

Observe that is zero at x = -5 and not defined at x = 5

Hence plotting these two points on number line

Now for x > 5, is positive

For every root and not defined value of the sign will change

We want greater than zero that is the positive part hence x < -5 and x > 5

x < -5 means x is from negative infinity to -5 and x > 5 means x is from 5 to infinity

Hence x ∈ (-∞, -5) U (5, ∞)

Hence solution of is x ∈ (-∞, 2) U (5, ∞)