A cricket team of 11 players is to be selected from 16 players including 5 bowlers and 2 wicketkeepers. In how many ways can a team be selected so as to consist of exactly 3 bowlers and 1 wicketkeeper?


There is a cricket team of 11 players is to be selected from 16 players, which must include 3 bowlers and a wicketkeeper.


there will be a team of 7 batsmen, 1 wicketkeeper and 3 bowlers.


there are 5 bowlers from which 3 is to be selected in 5C3 ways


there are two wicketkeepers out of which 1 is to be selected in2C1


hence, from 9 players left 7 is to be selected from that in 11C7 ways.


by Multiplication principle , we get


= 5C3 2C1 9C7


Applying nCr =


= 720 ways


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