A cricket team of 11 players is to be selected from 16 players including 5 bowlers and 2 wicketkeepers. In how many ways can a team be selected so as to consist of exactly 3 bowlers and 1 wicketkeeper?
There is a cricket team of 11 players is to be selected from 16 players, which must include 3 bowlers and a wicketkeeper.
 there will be a team of 7 batsmen, 1 wicketkeeper and 3 bowlers.
 there will be a team of 7 batsmen, 1 wicketkeeper and 3 bowlers.
 there are 5 bowlers from which 3 is to be selected in 5C3 ways
 there are 5 bowlers from which 3 is to be selected in 5C3 ways
⇒there are two wicketkeepers out of which 1 is to be selected in 2C1
2C1
 hence, from 9 players left 7 is to be selected from that in 11C7 ways.
 hence, from 9 players left 7 is to be selected from that in 11C7 ways.
 by Multiplication principle , we get
 by Multiplication principle , we get
= 5C3 2C1
 2C1 9C7
 9C7
Applying nCr = 
= 720 ways