Let X = {-1, 0, 3, 7, 9} and f : X → R : f(x) x3 + 1. Express the function f as set of ordered pairs.
Given: f: X → R, f(x) = x3 + 1
Here, X = {-1, 0, 3, 7, 9}
For x = -1
f(-1) = (-1)3 + 1 = -1 + 1 = 0
For x = 0
f(0) = (0)3 + 1 = 0 + 1 = 1
For x = 3
f(3) = (3)3 + 1 = 27 + 1 = 28
For x = 7
f(7) = (7)3 + 1 = 343 + 1 = 344
For x = 9
f(9) = (9)3 + 1 = 729 + 1 = 730
∴ the ordered pairs are (-1, 0), (0, 1), (3, 28), (7, 344), (9, 730)