Find the middle term in the expansion of :
(i) (3 + x)6
(ii) 
(iii) 
(iv) 
(i) For (3 + x)6,
a=3, b=x and n=6
As n is even,
is the middle term
Therefore, the middle term ![]()
General term tr+1 is given by,
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Therefore, for 4th , r=3
Therefore, the middle term is
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= (20). (27) x3
= 540 x3
(ii) For
,
, b=3y and n=8
As n is even,
is the middle term
Therefore, the middle term ![]()
General term tr+1 is given by,
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Therefore, for 5th , r=4
Therefore, the middle term is
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= (70). x4 y4
(iii) For
,
,
and n=10
As n is even,
is the middle term
Therefore, the middle term ![]()
General term tr+1 is given by,
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Therefore, for 6th , r=5
Therefore, the middle term is
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= -252
(iv) For
,
a=x2,
and n=10
As n is even,
is the middle term
Therefore, the middle term ![]()
General term tr+1 is given by,
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Therefore, for the 6th middle term, r=5
Therefore, the middle term is
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= -252 (32) x5
= -8064 x5