If the coefficients of x2 and x3 in the expansion of (3 + px)9 are the same then prove that
.
To prove: that. If the coefficients of x2 and x3 in the expansion of (3 + px)9 are the same then
.
Formula Used:
General term, Tr+1 of binomial expansion
is given by,
Tr+1
nCr xn-r yr where
nCr![]()
Now, finding the general term of the expression, (3 + px)9 , we get
Tr+1
9Cr![]()
For finding the term which has
in it, is given by
r=2
Thus, the coefficients of x2 are given by,
T3
9C2![]()
T3
9C2![]()
For finding the term which has
in it, is given by
r=3
Thus, the coefficients of x3 are given by,
T3
9C3![]()
T3
9C3![]()
As the coefficients of x2 and x3 in the expansion of (3 + px)9 are the same.
9C3
9C2![]()
9C3
9C2![]()
![]()
![]()
![]()
Thus, the value of p for which coefficients of x2 and x3 in the expansion of (3 + px)9 are the same is ![]()