Find the values of k for which k + 12, k – 6 and 3 are in GP.
To find: Value of k
Given: k + 12, k – 6 and 3 are in GP
Formula used: (i) when a,b,c are in GP b2 = ac
As, k + 12, k – 6 and 3 are in GP
⇒ (k – 6)2 = (k + 12) (3)
⇒ k2 – 12k + 36 = 3k + 36
⇒ k2 – 15k = 0
⇒ k (k – 15) = 0
⇒ k = 0 , Or k = 15
Ans) We have two values of k as 0 or 15