Find the equation of the line whose portion intercepted between the axes is bisected at the point (3, -2).
To Find: The equation of the line whose portion intercepted between the axes is bisected at the point (3, -2).
Formula used:
Let the equation of the line be
= 1
Since it is given that this equation , whose portion is intercepted between the axes is bisected i.e.; is divided into ratio 1:1 .
Let A(a,0) and B(0,b) be the points foring the coordinate axis.
a and b are intercepts of x and y-axis respectively.
By using mid-point formula (m:n = 1:1)
(x, y) =( =
Since given point (3 , -2) divides coordinate axis in 1:1 ratio
(x , y) = (3 , -2)
=3 and
= -2
a=6 b=-4
equation of the line : = 1
= 1
-4x +6y = -24
-2x +3y = -12
Hence the required equation of the line is 2x -3y = 12.