Using short cut method, find the mean, variation and standard deviation for the data :


xi



4



8



11



17



20



24



32



fi



3



5



9



5



4



3



1




To find: MEAN


(xi)



(fi)



xifi



4



3



12



8



5



40



11



9



99



17



5



85



20



4



80



24



3



72



32



1



32



Total



∑fi = 30



∑fixi =420



Now,



=14


To find: VARIANCE


(xi)



(fi)









4



3



4 – 14 = -10



(-10)2 = 100



3 × 100 = 300



8



5



8 – 14 = -6



(-6)2 = 36



5 × 36 = 180



11



9



11 – 14 = -3



(-3)2 = 9



9 × 9 = 81



17



5



17 – 14 = 3



(3)2 = 9



5 × 9 = 45



20



4



20 – 14 = 6



(6)2 = 36



4 × 36 = 144



24



3



24 – 14 = 10



(10)2 = 100



3 × 100 = 300



32



1



32 – 14 = 18



(18)2 = 324



1 × 324 = 324




N = 30









= 45.8


To find: STANDARD DEVIATION




= 6.77


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