Differentiate:
(3x – 5) (4x2 – 3 + ex)
To find: Differentiation of (3x – 5) (4x2 – 3 + ex)
Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)
(ii)
(iii)
Let us take u = (3x – 5) and v = (4x2 – 3 + ex)
Putting the above obtained values in the formula :-
(uv)′ = u′v + uv′
[(3x – 5)(4x2 – 3 + ex)]’ = 3×(4x2 – 3 + ex) + (3x – 5)×(8x + ex)
= 12x2 – 9 + 3ex+ 24x2 + 3xex – 40x - 5ex
= 36x2 + x(3ex – 40) – 9 - 2ex
Ans) 36x2 + x(3ex – 40) – 9 - 2ex