Solve for x:



To find: value of x


Formula Used:


Given:


LHS




Therefore,


Taking tangent on both sides, we get



⇒ 62x = 16 – 8x2


⇒ 8x2 + 62x – 16 = 0


⇒ 4x2 + 31x – 8 = 0


⇒ 4x2 + 32x – x – 8 = 0


⇒ 4x × (x + 8) – 1 × (x + 8) = 0


⇒ (4x – 1) × (x + 8) = 0



Therefore, are the required values of x.


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