Without expanding the determinant, prove that
SINGULAR MATRIX A square matrix A is said to be singular if |A| = 0.
Also, A is called non singular if |A| ≠ 0.
We know that C1⇒ C1-C2, would not change anything for the determinant.
Applying the same in above determinant, we get
Now it can clearly be seen that C1=8 × C3
Applying above equation we get,
We know that if a row or column of a determinant is 0. Then it is singular determinant.