Using properties of determinants prove that:
[R1’ = 3R1]
[R1’ = R1 - R2]
[R2’ = 2R2]
[R2’ = R2 - R3]
= (1/6)[0 + 0 + 6a{a(a + b) - a(2a + b) [expansion by first column]
= - a3
1
Using properties of determinants prove that:
[R1’ = 3R1]
[R1’ = R1 - R2]
[R2’ = 2R2]
[R2’ = R2 - R3]
= (1/6)[0 + 0 + 6a{a(a + b) - a(2a + b) [expansion by first column]
= - a3