Using properties of determinants prove that:

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Taking a, b, c from C1, C2, C3

Operating R1→R1-R3, R2→R2-R3

Taking (a2+b2+c2) common from R1, R2

Operating R3→R3+R1+R2

Taking (a2+b2+c2) common from C3 �

Expanding with C3
= abc(a2+b2+c2)3×1×(1-0)
= abc (a2+b2+c2)3
Hence proved