Prove that = - (a – b) (b – c) (c – a) (a2 + b2 + c2).
Operating R1→R1-R2, R2→R2-R3
Taking (a-b), (b-c) common from R1, R2 respectively
Operating R1→R1- R2
Taking (a-c) common from R1
Expanding with C1
= (a-c)(a-b)(b-c)×(2b2+2bc+2c2-ab-b2-bc-ac-bc-c2+a2+ab+ac)
=-(c-a)(b-c)(a-b)(a2+b2+c2)
Hence Proved