Mark the tick against the correct answer in the following:
If 
then x = ?
To find: Value of x
We have, 
Applying 
⇒ 
Applying 
⇒ 
Expanding along R1
⇒ [1{(x)(-2) – (6)(2)}] = 0
⇒ [1{-2x – 12}] = 0
⇒ -2x-12 = 0
⇒ -2x = 12
⇒ x = -6
1
Mark the tick against the correct answer in the following:
If then x = ?
To find: Value of x
We have,
Applying
⇒
Applying
⇒
Expanding along R1
⇒ [1{(x)(-2) – (6)(2)}] = 0
⇒ [1{-2x – 12}] = 0
⇒ -2x-12 = 0
⇒ -2x = 12
⇒ x = -6