Let the relation R be defined on N by a Rb iff 2a + 3b = 30. Then write R as a set of ordered pairs.
Given R = {(a, b) : 2a + 3b = 30} ∀ (a,b) ∈ N
Now according to the question 2a + 3b = 30:
⇒ R={(3,8),(6,6),(9,4),(12,2)}
NOTE: 0 is a whole number that’s why its not considered in this set, Although if we consider 0 as a natural number then the answer would be:
⇒ R={(0,10),(3,8),(6,6),(9,4),(12,2),(15,0)}