Write whether f : R → R given by
is one-one, many-one, onto or into.
(I)A function
is one-one function or an injection if
f(x)=f(y)
x=y for all x,y
A
or f(x)
f(y)
x
y for all x,y
A
(II) A function
is onto function or surjection if
Range (f)=co-domain(f)
(III) A function
is not onto function, then
is always an onto function
Given:-
(i)f : R → R
(ii)![]()
![]()
=x ± x
=0, 2x
Now putting x=0
![]()
Again putting x=-1
![]()
Hence f is many one