Write the equation of the plane parallel to XOY - plane and passing through the point (2, –3, 5)

Question

Philoid · Accepted Answer

Equation of XOY plane is z=0.

Since the required plane should pass through the point (2, - 3, 5).

We know, the vector equation of a plane perpendicular to a given direction and passing through a given point() is given by,

i.e.

⟹ (z - 5)=0

⟹ z=5

hereis given byas it is perpendicular to XOY plane, and here

Hence, the desired equation for the plane is z=5.