Write the equation of the plane parallel to YOZ - plane and passing through (–4, 1, 0).

Question

Philoid · Accepted Answer

Equation of YOZ plane is x=0.

Since the required plane should pass through the point ( - 4, 1, 0).

We know, the vector equation of a plane perpendicular to a given direction and passing through a given point() is given by,

i.e.

⟹ (x + 4)=0

⟹ x= - 4

hereis given by as it is perpendicular to YOZ plane, and here

Hence, the desired equation for the plane is x= - 4.