Write the plane in normal form.

The plane is given as, .

We can write the equation of the plane in general form as,

2x + 3y - 6z - 14=0 …………… (1)

Now, to get the normal form of a plane given in general form as, Ax + By + Cz + D=0 where …… (2), we have to divide the equation (1) by , where is the normal vector given as,

Now,

Comparing equation (1) with equation (2), we get, D= - 14

=2

[where p is the distance between the plane and the origin]

Normal form of the equation is given as,

Here, normal form of the given plane is,