Write the direction cosines of the line whose cartesian equations are 2x = 3y = –z.
We have
2x = 3y = -z
The equation of the given line can be re-written as,
The direction ratios of the line parallel to AB are proportional to → 3, 2, -6
The direction cosines of the line parallel to AB are proportional to →
, 
, 
, 
, 
1