The equation of tangent at those points where the curve y = x² – 3x + 2 meets x-axis are

Given that the curve y = x² – 3x + 2

The tangent passes through point (x, 0)

⇒ 0 = x² – 3x + 2

⇒ (x-2)(x-1)=0

⇒ x = 1 or 2

Equation of the tangent:

(y-y₁)=Slope of tangent×(x-x₁)

Case: 1

When x = 2

Slope of tangent = 1

Equation of tangent:

y = 1× (x – 2)

⇒ x – y – 2 = 0

Case: 2

When x = 1

Slope of tangent = -1

Equation of tangent:

y = -1× (x – 1)

⇒ x + y – 1 = 0

Hence, option B is correct.