Choose the correct answer.

Let f(x) = a + b |x| + c |x|4, where a, b, and c are real constants. Then, f(x) is differentiable at x = 0, if



Given that f(x) = a + b |x| + c |x|4, where a, b, and c are real constants and f(x) is differentiable at x = 0.



f(x) is differentiable at x =0


LHD = RHD







- b = b


2b = 0


b = 0

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