Mark the correct alternative in the following:

The coordinates of the point on the ellipse 16x²+9y²=400 where the ordinate decreases at the same rate at which the abscissa increase, are:

Taking ellipse to be 16x²+9y²=400 instead of 46x²+9y²=400

Let E(x,y):16x²+9y²=400

Solving for y, we get

- (1)

Given that , we have to calculate x,y

Differentiating (1) with respect to t, we get

Substituting values, we get

Simplifying the equation, we get

Squaring both sides

256x²=9(400-16x²)

Solving the equation, we get

x²=9

x=±3

Substituting in (1), we get

By seeing the graph of E(x,y), we can conclude that the point has to lie in I^st or III^rd quadrant, as only in these quadrants, the increase in abscissa leads to decrease in ordinate.

Hence the points are