#Mark the correct alternative in each of the following
The maximum value of x1/x, x > 0 is
.
Let
therefore,.
Differentiating w.r.t x
so,
Now, lets put y’=0
soOR
1-log x) =0
therefore,x=1/e and x=0
Hence by second derivative test
f’’(1/e)<0 so it’s a point of maximum
and maximum value is.