#Mark the correct alternative in each of the following

The minimum value of is

f’(x)=0

_logx-1=0

_{⇒ x=e}

_{for second derivative we find f’(x)}

Hence by second derivative test

f’’(x)>0 so it’s a point of minimum.

therefore,

x=e is a point of minimum

so minimum value is f(e)=e