#Mark the correct alternative in each of the following

If x lies in the interval [0, 1], then the least value of x2 + x + 1 is



f(x)=


f’(x)=


f’(x)=0


⇒2x+1=0


⇒ x= - �


At extreme points,


f(0)=0


f(1)=1+1+1>0


so,x=1 is a least value.


Option(C)

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