Evaluate
We can write above integral as
Considering first integral:
Since the numerator and denominator are exactly same, our integrand simplifies to 1 and integrand becomes:
⇒ ∫ dx
⇒ x
--- (3)
Considering second integral:
Let u = 1 + ex, du = exdx
Apply u – substitution:
Replacing the value of u we get,
---(4)
From (3) and (4) we get,