equals

Let, sin x = t

Differentiating both side with respect to x

⇒ dt = cos x dx

At x = 0, t = 0

At x = π2, t = 1

By using the concept of partial fraction

1 = A(1 + t) + B(2 + t)

1 = (A + 2B) + t(A + B)

A + 2B = 1, A + B = 0

A = -1, B = 1

y = [(-log 3 + log 2) – (-log 2 + log 1)]