Mark the correct alternative in each of the following:
For non-zero vectors a⃗, b⃗ and c⃗ the relation
holds good, if
Let ![]()
--------(1) (∵ α is angle between a⃗ and b⃗ )
Then ![]()
(∵θ is angle between e⃗ and c⃗ ⇒ θ is angle between a⃗ Xb⃗ and c⃗ )
(∵ using (1))
Hence,
if and only if ![]()
if and only if
and ![]()
if and only if
and ![]()
⇒ a⃗ and b⃗ are perpendicular.
Also e⃗ is perpendicular to both a⃗ and b⃗ .
θ=0⇒ c⃗ is perpendicular to both a⃗ and b⃗
∴ a⃗, b⃗, c⃗ are mutually perpendicular.
∴ a⃗∙ b⃗=b⃗∙ c⃗=c⃗∙ a⃗=0