Mark the correct alternative in each of the following:
A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement, then the probability that exactly two of the three balls were red, the first ball being red, is
C. 15/28 D. 5/28
Total Red Balls = 5
Total Blue Balls = 3
M = Event getting Red ball
N = Event getting Blue ball
Now,
P(Getting exactly 2 red balls of 3 balls, the first ball being red) →
→ (Since 1st ball is already red, P(red ball) =
and so on..)