Find the equation of the circle, the coordinates of the end points of one of whose diameters are

A( - 2, - 3) and B( - 3, 5)

The equation of a circle passing through the coordinates of the end points of diameters is:

(x - x₁) (x - x₂) + (y - y₁)(y - y₂) = 0

Substituting, values:(x₁, y₁) = ( - 2, - 3) & (x₂, y₂) = ( - 3, 5)

We get:

(x + 2)(x + 3) + (y + 3)(y - 5) = 0

⇒ x² + 3x + 2x + 6 + y² - 5y + 3y - 15 = 0

⇒ x² + y² + 5x - 2y - 9 = 0

Ans: x² + y² + 5x - 2y - 9 = 0