Find the equation of the parabola, which is symmetric about the y-axis and passes through the point P(2, -3).


The equation of a parabola with vertex at the origin and symmetric about the y-axis is


x2 = 4ay


Since point P(2,-3) passes through above parabola we can write,


22 = 4a(-3)


• 4 = -12a



Therefore, the equation of a parabola is




• 3x2 = -4y



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